Question 1142487

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The outcomes and their probabilities are:

YY  (7/12)(6/11) = 42/132  
YR  (7/12)(3/11) = 21/132  
YB  (7/12)(2/11) = 14/132
 
RY  (3/12)(7/11) = 21/132
RR               = 6/132
RB               = 6/132

BY               = 14/132
BR               = 6/132
BB               = 2/132
                -----------
          Total  = 132/132


Adding the two entries RB and BR:  (6+6)/132 = 12/132 = {{{ highlight(1/11)}}}