Question 1142423
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The two trains will be 50 miles apart after one hour.<br>
So if the two speeds in miles per hour are x and x+10,<br>
{{{x^2+(x+10)^2 = 50^2}}}
{{{x^2+x^2+20x+100 = 2500}}}
{{{2x^2+20x-2400 = 0}}}
{{{x^2+10x-1200 = 0}}}
{{{(x+40)(x-30) = 0}}}<br>
You can finish....