Question 1142353
Since you are given three choices, you can just plug in the values...

Example (0,0) -->  x=0, y=0:  {{{ 2x - y = 2(0)-0 = 0 <> -3 }}}  so (0,0) is NOT a solution.<br>

Do the same for the other two choices, one of them should work.


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Another approach...

Solve the system directly:
2x - y = -3    (1)
x + y = 0      (2)

Adding these equations eliminates 'y':
3x = -3 
 x = -1  -->  y = 1    Hence (-1,1) is a solution

There you have it.