Question 1142381
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The critical points of the rational function {{{(2x-5)/(3-x)}}} are the x values that make the numerator or denominator 0.  Those values are x=5/2 and x=3.  Note that x=5/2 is valid because 0 in the numerator is okay; x=3 is not valid because 0 in the denominator is not valid.<br>
The zeroes of {{{y = 2x^2-11x+15 = (2x-5)(x-3)}}} are also x=5/2 and x=3.<br>
The critical values of both functions divide the number line into 3 intervals: (-infinity,2.5), (2.5,3), and (3,infinity).<br>
(1) Determine on which interval(s) the rational function is greater than or equal to 0, paying attention to whether the endpoints of each interval are included.<br>
(2) For those intervals, determine whether the graph of 2x^2-11x+15 is above or below the x-axis.<br>
(3) Select the correct answer choice.