Question 1142403
Find the equation of the line containing the points (4,-2) and (1,3).
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Don't put a space after the comma.
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It's not "the equation" it's an equation.
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There's more than 1 way to find them.
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Find the slope, m
m = diffy/diffx = 5/-3 = -5/3
Then, x-x1 = m*(y-y1) where (x1,y1 is either point.
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x-1 = (-5/3)*(y-3)
That's an equation.
1-x = (5y/3) - 5
That's an equation.
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<pre>

|x   y   1|
|4  -2   1| = 0
|1   3   1|
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x*(-2*1 - 3*1) - y*(4*1 - 1*1) + 1*(4*3 - 1*-2) = 0
-5x - 3y + 14 = 0
</pre>
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That's an equation.
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You can check for mistakes.
Sub for x & y in each equation.