Question 1142370
Find all solutions of the equation in the interval [0,2π).
-cosx = -sin^2x-1
Add parentheses:
-cos(x) = -sin^2(x) - 1
Is that what you meant?
------------
cos(x) = sin^2(x) + 1
{{{cos(x) = 1 - cos^2(x) + 1}}}
=========
Can you do the rest?
======================
Do NOT say this:
If there is more than one solution, separate with commas.
What would we do if we don't have any commas?