Question 1142268
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If you take p= 0.4, q= 0.6,  then the solution is as follows.


    Probability(more than 7 of them weight 65 pounds or more) = P(8) + P(9) + P(10).


Further,


    P(8) = {{{C[10]^8*p^8*q^2}}} = {{{((10*9)/(1*2))*0.4^8*0.6^2}}} = 0.010617;


    P(9) = {{{C[10]^9*p^9*q^1}}} = {{{10*0.4^9*0.6}}}       = 0.001573;


    P(10) = {{{p^10}}}           = {{{0.4^10}}}       = 0.00105.


I leave it to you to add these numbers and to get the numerical value of the answer.
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It is how such problems are to be solved.


In your post, you didn't explain what the "x" is, so I do not touch this issue.