Question 1142263
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Since x^2 + bx + 18 is factored as (x+2)*(x+c), it means that x= -2 is the root of the polynomial x^2 + bx + 18 :


    (-2)^2 + b*(-2) + 18 = 0,

    4       -2b     + 18 = 0,

    4 + 18 = 2b  ====>  2b = 22  ====>  b = 11.



Next, according to Vieta's theorem, the constant term 18 of the polynomial x^2 + bx + 18  is the product of its roots.


One of the root is x= -2.  Hence, the other root is  {{{18/(-2)}}} = -9.

From the other side, the other root is x= -c.  

Hence,  c= 9.


<U>ANSWER</U>.  b = 11;  c = 9.
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Solved.