Question 1142231
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Represent the function equivalently in the form


{{{(x^2-3x)/(x+1)}}} = {{{(x^2 + x)/(x+1))}}} - {{{(4x)/(x+1)}}} = {{{(x*(x+1)/(x+1))}}} - {{{(4x+4)/(x+1)}}} + {{{4/(x+1)}}} = {{{x}}} - 4 + {{{4/(x+1)}}}.


The first two terms produce the "table integrals".


The third term integral  is  4*log(|x+1|).


Do not forget to include the "arbitrary constant term C" in your final answer (!)
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