Question 104808
Let amount of nickels = n, amount of quarters = (n+4), and amount of dimes = (37-n).

So, {{{.05n +.25(n+4)+.10(37-n) = 5.50}}}
{{{.05n+.25n+1.00+3.70-.10n = 5.50}}}
{{{.20n+4.70 = 5.50 }}}
{{{.20n+4.70 = 5.50}}}
{{{.20n+4.70-4.70 = 5.50-4.70}}}
{{{.20n =.80}}}
{{{n = 4}}}
So, 4 nickels, 8 quarters, and 33 dimes.

Good Luck!