Question 1142022
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If b is his speed without wind, then b+4 is his speed with the wind, and b-4 is his speed against the wind.<br>
The time to bike 57 miles with the wind is 57/(b+4); the time to bike 33 miles against the wind is 33/(b-4).<br>
The problem tells us those two times are the same, so<br>
{{{57/(b+4) = 33/(b-4)}}}<br>
Solve using basic algebra....