Question 1141992
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<pre>

Let "a" be the number of adults;  then the number of children is  (2a).


The number of students is the rest, (207-a-2a) = 207-3a.


The "money" equation is


    12a + 5*(2a) + 7*(207-3a) = 1498  dollars.


Simplify and solve for "a".


    12a + 10a + 7*207 - 21a = 1498,

    a = 1498 - 7*207

    a = 49.


<U>ANSWER</U>.  49 adults;  2*49 = 98 children  and  (207-3*49) = 60 students.
</pre>

Solved.


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This problem is to be solved using one equation in one unknown.


If you want to see many other similar solved problems, look into the lessons

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