Question 1141977
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Here is an easy alternative to the standard algebraic solution method shown by the other tutor; this method can be used on a wide variety of "mixture" problems.<br>
(1) $1200 all at 6% would give $72 interest; all at 8% would give $96 interest.<br>
(2) The actual interest, $88, is 2/3 of the way from $72 to $96.  (Picture the three interest amounts $72, $88, and $96 on a number line; 88 is 2/3 of the way from 72 to 96.)<br>
(3) Therefore 2/3 of the total investment needs to be at the higher rate.<br>
ANSWER: 2/3 of $1200 = $800 at 8%; 1/3 of $1200 = 400 at 6%.<br>
CHECK: 400(.06)+800(.08) = 24+64 = 88