Question 1141925
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Don't mix cases.  In a single problem, F(x) and f(x) could be very different functions.<br>
1. f(g(x)) = f(x+3) = 10(x+3)<br>
2. inverse of f(g)<br>
g adds 3 to the input; f multiplies the input by 10.
So f(g(x)) adds 3 to the input and then multiplies it by 10.
The inverse does the opposite operations in the opposite order: divide by 10 and subtract 3.<br>
ANSWER: inverse of f(g(x)) = (x/10)-3<br>
3. inverse of g(f)<br>
(similar explanation...)<br>
ANSWER: inverse of g(f(x)) = (x-3)/10<br>