Question 1141867

4x-3y=-1
3x-y=-2

Substitution!!!
how plz
<pre>{{{system(matrix(1,6, 4x - 3y, "=", - 1, "-----", eq, "(i)"), matrix(1,6, 3x - y, "=", - 2, "------", eq, "(ii)"))}}}

Since y now has a coefficient of - 1, you can easily solve in terms of y, as follows:
3x - y = - 2
3x = - 2 + y ---- Adding y to each sides
3x + 2 = y ------ Adding 2 to both sides
4x - 3(3x + 2) = - 1 ----- Substituting 3x + 2 for y in eq (i)
4x - 9x - 6 = - 1
- 5x = 5
{{{highlight_green(matrix(1,5, x, "=", 5/(- 5), "=", - 1))}}}


3(- 1) - y = - 2 -------- Substituting - 1 for x in eq (ii)
- 3 - y = - 2-
- y = - 2 + 3
- y = 1
{{{highlight_green(matrix(1,5, y, "=", 1/(- 1), "=", - 1))}}}</pre>