Question 1141867
4x-3y=-1
3x-y=-2

Substitution!!!
how plz
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<pre>
From the first equation, 
  add 3y to each side -->  4x = -1+3y 
  divide each side by 4 -->  x = (-1+3y)/4 = (-1/4) + (3y/4)

Substitute the right hand side of this last equation for "x" in the 2nd equation:
   3( (-1/4) + (3y/4) )  - y = -2
   
   multiply paren contents by 3 (this is distributive property of multiplication):  
      (-3/4) + (9y/4)  - y = -2
  
   add  3/4 to each side -->  (9y/4) - y = -2 + 3/4
   LHS & RHS over common denom -->   (9y/4)-(4y/4) = (-8/4) + (3/4)

   multiply both sides by 4 -->    9y - 4y = -8 + 3
    combine like terms  --->       5y = -5
    divide both sides by 5 --->     y = -1 

     substitute y=-1 into one of original two equations --> 3x -(-1) = -2
                      3x + 1 = -2
       subtract 1 from both sides -->  3x = -3
          divide both sides by 3  -->   x = -1
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Ans:  x=-1 and y=-1.  
 
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Check by plugging these values into original equations:
     4x - 3y =  4(-1) - 3(-1) = -4 + 3 = -1  (ok)
     3x - y = 3(-1) - (-1) = -3 + 1 = -2  (ok)


You're welcome.