Question 1141856
Some of but NOT a finished solution:

Draw the described figure.  YZ along the ground, YE a hypotenuse;
Triangle YZE.
On top of that triangle another sharing side YE with the on-the-ground triangle, triangle XYE.


YZ = 12;
ZE = 1.5
X is top of the pole.  Y is on the ground.
m of angle YZE is 90 degrees.


{{{YE=sqrt(1.5^2+12^2)}}}


{{{sin(EYZ)/1.5=sin(90)/YE}}}


{{{sin(EYZ)=1.5/sqrt(1.5^2+12^2)}}}
from which find
m of angle {{{EYZ= arcsin(1.5/sqrt(1.5^2+12^2))}}}

and from that find
measure of angle XYE = {{{90-arcsin(1.5/sqrt(1.5^2+12^2))}}}.


You want to solve for XY.
You would now have found known:
meas angle XYE;
meas angle YEX (fifty degree);
length YE;
AND YOU CAN COMPUTE ANGLE YXE having now already two of the upper triangles angle measures.


From there use Law Of Sines to find XY.