Question 1141851
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This volume is the difference


      the volume of the cylinder of the radius  r= 1  and the height  h= 1


          MINUS


      the volume of the cone with the base radius  r= 1  and the height  h= 1.


So, the requested volume is  {{{pi*r^2*h}}} - {{{(1/3)*pi*r^2*h}}} = {{{(2/3)*pi*r^2*h}}} = {{{(2/3)*pi*1^2*1}}} = {{{(2/3)*pi}}} = {{{(2/3)*3.14}}} = 2.093 cubic units.
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