Question 1141853
LF 1 has an x-intercept at (8, 0), because when x=8, y=0 (x-axis)
LF 2 has two known points, at (4, 2) and (8, 0)
slope between these is -2/4 or -1/2

point slope formula y-y1=m(x-x1), m slope and (x1, y1) a point
y=-(1/2)(x-8)
y=-(1/2)x+4 is the function
when x=-4, y or k, the answer, is 6

{{{graph(300,300,-10,10,-10,10,-2x+16,-(x/2)+4)}}}