Question 1141817
That is log(x,(1/125))=5
OR
{{{log(x,(1/125))=5}}}.


{{{log(x,5^(-3))=5}}}


{{{-3*log(x,5)=5}}}


{{{log(x,5)=-5/3}}}


{{{x^(-5/3)=5}}}----------in exponential form


{{{(x^(-5/3))^(-3/5)=5^(-3/5)}}}


{{{x=5^(-3/5)}}}OR  {{{x=1/(5^(3/5))}}}

about 0.3807307877