Question 104686
How many ounces of water must be added to 100 ounces of 40% antifreeze solution to obtain a 16% solution
x= ounces of water
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Original solution;
100 ounces, 40% antifreeze= .40(100)=40
New solution = .16(100+x)= 16+.16x
equation;
40=16+.16x
24=.16x
150=x
:)