Question 15346
3 + 2(4a - 3)= 5 
{{{3 + 2*4a - 2*3= 5}}}
3 + 8a - 6= 5
8a= 5-3+6
8a= 2+6
8a= 8 ----------->Divide by 8
a=1
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and 
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4 - 3(2 - 3b) = 11
{{{4 - 3*2 - (-3)*3b = 11}}}
4 - 6 + 9b = 11
9b = 11+6-4
9b = 11+2
9b = 13 --------->Divide by 9
{{{b=13/9=1&4/9}}}
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Thus b>a.
OK