Question 1141765
Draw your picture and label all parts.


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"radius of 7(square root of 2) ft (from the center of the square to any vertex)"
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There are eight special 45-45-90 triangles; hypotenuse is  {{{7sqrt(2)}}}.  You know what to do from here.... right?


x, the side for a leg of one of those triangles; which is also half the length of the side of the original square figure.


{{{x^2+x^2=(7sqrt(2))^2}}}
You can find the necessary steps from this...