Question 1141728


A regular pentagon has a side length of 8 inches.
perimeter of the pentagon is
{{{P=5*8in}}}
{{{P=40in}}}
 
if a square has the same perimeter as the pentagon, than  {{{P=4a}}}=>{{{4a=40in}}}=>{{{a=10in}}}

so, the area of the square will be: 

{{{A=a^2}}}

{{{A=(10in)^2}}}

{{{A=100in^2}}}