Question 1141669
{{{(V^2*sin^2(x))/(2g^"")=(V^2*tan^2(x))/(2g*sec^2(x))}}}
<pre>
Work on the right side

              {{{(V^2*tan^2(x))/(2g*sec^2(x))}}}


              {{{(V^2/(2g))*(tan^2(x)/sec^2(x))}}}

              {{{(V^2/(2g))*((sin^2(x)/cos^2(x))/(1^""/cos^2(x)))}}}

              {{{(V^2/(2g))*(sin^2(x)/cos^2(x))*(cos^2(x)/1^""))}}}

              {{{(V^2/(2g))*(sin^2(x)/cross(cos^2(x)))*(cross(cos^2(x))/1^""))}}}

              {{{(V^2/(2g))*(sin^2(x)/1^"")}}}

              {{{(V^2*sin^2(x))/(2g^"")}}}

[The {{{V^2/(2g)}}} factor on both sides was just "extra baggage".]

Edwin</pre>