Question 1141623
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Unfortunately none of these choices work. Let's go through them one by one to see why. 

<ol type="A"><li>If you sold 0 lemons, then the chances of picking a cherry are 7/24 = 0.2917 = 29.17% approximately</li><li>If you sold 1 lemon, then the chances of picking a cherry are 7/23 = 0.3043 = 30.43% approximately</li><li>If you sold 2 lemons, then the chances of picking a cherry are 7/22 = 0.3182 = 31.82% approximately</li><li>If you sold 3 lemons, then the chances of picking a cherry are 7/21 = 1/3 = 0.3333 = 33.33% approximately</li></ol>As you can see, we don't get anywhere close to 50%. The highest we get is roughly 33.33%


So there seems to be a typo with this problem. Please ask your teacher for clarification and/or corrections. 


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Side note: If we sold all 9 lemons, then the only way to have a 50% shot at getting a cherry is that we must have the same number of cherries and oranges. The fact that we have 7 cherries and 8 oranges means that the chances of picking a cherry are less than 50%. This is because there are less cherries compared to oranges.
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