Question 1141538
General Term:  {{{A+d(n-1)}}}


Term n=4:   {{{A+3d}}}
Term n=2:   {{{A+d}}}

Term n=6:   {{{A+5d=7}}}



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fourth term of an Arithmetic Progression (A.P) is one less than twice the second term.
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{{{A+3d=2(A+d)-1}}}
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{{{A+3d=2A+2d-1}}}
{{{d=A-1}}}


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Solve this system:  {{{system(A+5d=7,d=A-1)}}}