Question 1141202
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First, let us calculate the number of all possible five digit numbers formed using the digits 0, 1, 2, 3 and 4 without repetition.


The leftmost digit can be any of four digits 1, 2, 3 or 4, which gives 4 options.


The next digit can be any of 4 remaining digits, which gives 4 options.


Using similar arguments, you will get 4*4*3*2*1 = 96 for the number of all possible five digit numbers formed 
using the digits 0, 1, 2, 3 and 4 without repetition.


The numbers divisible by 10 are those of them that ended by 0 (by zero),
and the number of such numbers is 4*3*2*1 = 24.


Thus the probability  P  under the question is the ratio  


    P = {{{24/96}}} = {{{1/4}}} = 0.25 = 25%.      <U>ANSWER</U>
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