Question 1141460
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Let N be that unknown number.


Consider the number (N+1).


Then from the condition, (N+1) is divisible by 2; is divisible by 5; and gives the remainder of 4 when is divided by 9.


So, we should find (N+1) as the number multiple of 10, which gives the remainder of 4 when is divided by 9.


Try 10, 20, 30, 40,  and you quickly will find that  N+1 = 40 satisfies these condition.


So, N = 40-1 = 39.      <U>ANSWER</U>
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To get more training in solving such problems, see the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/divisibility/lessons/The-number-that-leaves-a-remainder-1-when-divided-by-2-by-3-by-4-by-5-and-so-on-until-9.lesson>The number that leaves a remainder 1 when divided by 2, by 3, by 4, by 5 and so on until 9</A>

in this site.