Question 1141449
There are 6^2 = 36 possible events 
:
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
:
The event/s with a sum of 6 are (1,5), (2,4), (3,3), (4,2), (5,1)
:
The event/s with a sum of 12 is (6,6)
:
Probability(sum is 6 or 12) = 5/36 + 1/36 = 6/36 = 1/6
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