Question 1141429
let x be the amount of water and y be the amount of the 10% lidocaine lotion
:
x + y = 800 mL
:
0.025 * 800 = 20 mL of lidocaine
:
y = 800 -x
:
0.0 * x + 0.10 * (800 -x) = 20
:
80 -0.10x = 20
:
-0.10x = -60
:
x = 600
:
y = 800 -600 = 200
:
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mix 600 mL of water with 200 mL of the 10% lidocaine lotion
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