Question 1141405
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The solution by the other tutor is incorrect.<br>
x^(1/2) is the square of x^(1/4); so this is a quadratic equation in which the "variable" is x^(1/4).  With experience most students can solve it in its given form.  But for most students it helps to define a new variable y=x^(1/4).  Then the equation is<br>
{{{y^2-9y+20 = 0}}}<br>
That equation is easily solved by factoring.<br>
(Then remember the values of y are not the answers to the original question....)