Question 1141232
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Angle B, an interior angle of a regular pentagon, is 108 degrees.<br>
Angles ABE and CBD, being base angles in isosceles triangles with vertex angles of 108 degrees, are each 36 degrees.<br>
That makes angle EBD 36 degrees.<br>
Then angle ABD is angle ABE plus angle EBD, which is 36+36 = 72 degrees.