Question 1141180
So what we're going to do here is elimination method:

1. Multiply the first one with 4 and 5 on the latter(since we wanted to cancel out
the y)
-------------------------------------
{{{4*(2x-5y)=(7)*4}}}
{{{5*(3x+4y)=(2)*5}}} 

2. Add the second eq. from the first one
-------------------------------------
{{{8x-20y=28}}}
{{{15x+20y=10}}} 

Hence, this would be like this:
=====================================
{{{23x=38}}}

3. Divide both sides with 23 to isolate x and here we get:
---------------------------------------------------------
{{{x=38/23}}}

Now we have x and we could substitute it to any of the equations. From this point, I'll choose for the first eq.

4. Plug in x and subtract it from the left side to transfer it from the right side(applying subtraction property)
---------------------------------------------------------
    4.1 {{{2(38/23)-5y=7}}}
        4.2{{{(76/23)-(76/23)-5y=7-76/23}}}
             4.3{{{-5y=7-76/23}}}
     From 4.3 Multiply 23 to 7 and subtract it with 76 and you get:
             {{{-5y=85/23}}}
5. Divide both sides with -5 to isolate y and here we get:
---------------------------------------------------------
{{{y = -85/(23*5)}}}
{{{y = -85/115}}}
{{{y = -17/23}}}

So our solution for the equations is ( {{{38/23}}} ,{{{-17/23}}} )