Question 1141045
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1) equation of line L<br>
The slope of the line through P and Q is -5/4; the slope of a line perpendicular to that line is 4/5.  Given a perpendicular through P, you have a point and a slope which you can use with either the slope-intercept or point-slope form of a linear equation to find the equation of line L.<br>
2) coordinates of point R (x-intercept of line L)<br>
In the equation from part 1, set y=0 and solve for x.<br>
3) area of triangle QPR (not OPR)<br>
The base is QR; since QR is on the x-axis, the height of the triangle is the y coordinate of P.  Use area = one-half base times height.