Question 1141003
the orientation will be like this:
2(x+1)+3(x+3)+(x+5) = 412

where:
2 times the 1st -> 2(x+1)
3 times the 2nd -> 3(x+3)
1 times the 3rd -> (x+5)

Thus,

6x + 16 = 412
6x = 396
x = 66

so the numbers would be

[66+1, 66+3, 66+5]
[67, 69, 71]

to check if it's true
2(66+1)+3(66+3)+(66+5)= 412
134 + 207 + 71 = 412

412 = 412

Hope to do your homework well. Goodluck