Question 1140923
h(t)= -6t^2 +32T +3
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be consistent in the formula, I assume T = t, then
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h(t)= -6t^2 +32t +3
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the t^2 coefficient does not look right(should be -16 instead of -6) but I will use the formula as you have stated it
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the x-axis is time and the y-axis is height
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time when maximum height is reached is the x-coordinate of the parabola's vertex
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Note the graph of this equation is a parabola that curves downward
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time when maximum height is reached = -b/2a = -32/2(-6) = 32/12 = 8/3 = 2 and 2/3 seconds
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Note general form of a quadratic is ax^2 +bx +c
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