Question 1140867
total acres are 70.
farmer has seeds to plan either potatoes or corn or both.
seed for potatoes is 20 dollars per acre.
see for corn is 60 dollars per acre.
total money for seed is 3000.
profit per acre of potatoes is 150 dollars.
profit per acre of corn is 50 dollars.


this problem can be solved graphically.


x = number of acres of potatoes
y = number of acres of corn.


objective function is profit = 150 * x + 50 * y


this is the function you want to maximize.


constraints are:


x >= 0
y >= 0
20 * x + 60 * y <= 3000
x + y <= 70


using the desmos.com calculator, you would graph the opposite of these inequalities.


the area on the graph that is not shaded is your region of feasibility.


the corner points of this area will be where the maximum profit lies.


the graph looks like this:


<img src = "http://theo.x10hosting.com/2019/051103.jpg" alt="$$$" >


the corner points of the reasible region are:


(0,50), (30,40), (70,0), (0,0)


profit at each of these corner points are:


0 * 150 + 50 * 50 = 2500 for (0,50)
30 * 150 + 40 * 50 = 6500 for (30,40)
70 * 150 + 0 * 50 = 10500 for (70,0) *****
0 * 150 + 0 * 50 = 0 for (0,0)


maximum profit is attained when all 70 acres are planted by potatoes.


all constraints need to be satisfied as well.


constraints are:


x >= 0 = satisfied
y >= 0 = satisfied
20 * x + 60 * y <= 3000 = 20 * 70 + 60 * 0 <=3000 = 1400 <= 3000 = satisfied
x + y <= 70 = 70 + 0 <= 70 = 70 <= 70 = satisfied.


all constraints were satisfied, therefore the solution looks good.


the solution is that all 70 acres should be planted by potatoes for maximum profit, based on the information provided in the problem.