Question 1140853
{{{M[1]V[1]=M[2]V[2]}}}-----But this is not the formula you need in your example.


The formula you actually need is different.


0.175 L of 3.0 M HCl mix with  0.115 L of 6.0 HCl;
Total volume is  {{{0.175L+0.115L=0.290L}}}.


Total moles of HCl:
{{{0.175*3+0.115*6=1.215*moles}}}


Resulting Concentration:

{{{1.215/0.29=highlight(4.2)}}} MOLAR


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Your formula is, for V in liters and M in molarity
{{{(M[1]V[1]+M[2]V[2])/(V[1]+V[2])=M[r]}}}

subscript "r" for "resulting mixture"