Question 1140824
{{{(y+1)/(y^2-4) - 5/(y+2)}}}
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{{{y^2-4 = (y-2)*(y+2)}}}
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{{{(y+1)/((y-2)*(y+2)) - 5/(y+2)}}}
= {{{(y+1)/((y-2)*(y+2)) - 5(y-2)/((y-2)*(y+2))}}}
= {{{(y+1)/((y-2)*(y+2)) - (5y-10)/((y-2)*(y+2))}}}
= {{{(-4y+11)/((y-2)*(y+2))}}}
= {{{(-4y+11)/(y^2-4)}}}