Question 1140717
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{{{p=q-10}}}
{{{p(q+15)=350}}}<br>
Solve the pair of equations simultaneously.  With one equation specifically defining p in terms of q, substitution is easiest:<br>
{{{(q-10)(q+15) = 350}}}
{{{q^2+5q-150 = 350}}}
{{{q^2+5g-500 = 0}}}<br>
Factor and solve, then choose the positive solution....