Question 1140781

{{{x+y=6}}}.......eq.1
{{{x-y=2}}}.......eq.2
----------------------add both

{{{x+y+x-y=6+2}}}

{{{2x+cross(y)-cross(y)=8}}}

{{{x=8/2}}}

{{{x=4}}}

go to {{{x+y=6}}}.......eq.1 plug in {{{x}}} value

{{{4+y=6}}} 

{{{y=6-4}}} 

{{{y=2}}}