Question 1140649
<br>
He started with 46 more $5 notes than $10 notes.<br>
He took out $545 in $5 notes; that is 545/5 = 109 $5 notes.<br>
So then he had 109-46 = 63 FEWER $5 notes than $10 notes.<br>
At that point he had 8 times as many $10 notes as $5 notes.<br>
You might be able to solve the problem mentally from there....<br>
Or use algebra:<br>
Let x = number of $5 notes left
Then 8x = number of $10 notes<br>
The number of $5 notes is now 63 less than the number of $10 notes:<br>
{{{x = 8x-63}}}<br>
Easily solved with basic algebra.<br>
Then, knowing the numbers of $5 and $10 notes at the end, you can easily answer both of the given questions.