Question 1140655
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Let x be the amount invested at 15%; then the amount invested at 6% is 5581-x.<br>
The interest from x at 15% is .15(x); the interest from (5581-x) at 6% is.06(5581-x).<br>
The problem says the amount of interest earned at 15% is 261.54 more than the interest earned at 6%:<br>
{{{.15(x) = .06(5581-x) + 261.54}}}<br>
Solve using basic algebra.