Question 1140588
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Two points determine a line.  So the question is about how much effort it takes to find two points for a given equation.<br>
If the equation is given in Ax+By=C form, then it is easiest to set x=0 to find the y-intercept and set y=0 to find the x-intercept.  For example....<br>
{{{3x+4y=12}}}<br>
When x=0, y = 12/4 = 3, so one point is (0,3); when y=0, x = 12/3 = 4, so the second point is (4,0).<br>
If the equation is given in y=Ax+B form, you immediately know the slope and the y-intercept.  So the first point is the y-intercept, and a second point can be found using the y-intercept and the slope.  For example....<br>
{{{y = -2x+5}}}<br>
The y-intercept (when x=0) is 5, so the first point is (0,5).<br>
A second point can be found starting at the known first point and moving according to the slope of -2.  A slope of -2 means 1 unit right and 2 units down from the known point (0,5), giving you a second point (1,3).<br>
You can provide your own additional examples, and further explanation, if required.