Question 1140509
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<pre>
Let x = amount at 8%, in dollars.

Then the amount at 6% is the rest (2050-x) dollars.



The interest from the 8% amount is 0.08*x  dollars.

The interest from the 6%   amount is 0.06*(2050-x)   dollars.



Your equation is


    interest at 8% - 2*(interest at 6%)  = 54 dollars,   or


    0.08*x         - 2*0.06*(2050-x)     = 54   dollars.


From the equation, express x and calculate the answer


    x = {{{(54 + 2*0.06*2050)/(0.08+2*0.06)}}} = 1500.


<U>Answer</U>.  The amount at 8% is $1500;  the rest  $2050-$1500 = $550 is the amount at 6%.


<U>Check</U>.   0.08*1500 - 2*0.06*550 = 54 dollars.   ! Correct !
</pre>

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It is a typical and standard problem on investment.


To see many other similar solved problems on investment, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.