Question 1140512
{{{f(x)=x^3+1}}}
{{{y = x^3 + 1}}}
to find the inverse, swap x and y
{{{x = y^3 + 1}}}
solve for y
y^3 = x - 1
Find the cube root of both sides
y = {{{3sqrt(x-1)}}}
{{{f(x^-1) = 3sqrt(x-1)}}}