Question 1140456
<br>
((6y)/(6y-14))÷((21)/(9y-21))÷((y^2)/(35))<br>
The form of the expression is A÷B÷C, where each of A, B, and C is a fraction.<br>
(1) perform the divisions in order, left to right
(2) change division of fractions to multiplication of the reciprocals<br>
{{{(6y/(6y-14))*((9y-21)/21)*(35/y^2)}}}<br>
Factor the common factors out of the binomials....<br>
{{{(6y/(2(3y-7)))*((3(3y-7))/21)*(35/y^2)}}}<br>
Then simplify by canceling all factors common to both numerator and denominator.