Question 1140376
{{{(x^2-4)/(8-x^3)}}} 
:
{{{(x^2-4)/(2^3-x^3)}}} 
The denominator is the difference of cubes, which factors
{{{((x-2)(x+2))/((2-x)(4+2x+x^2))}}}
factor out -1 in the denominator
{{{(-1(x-2)(x+2))/(-1(x-2)(4+2x+x^2))}}}
cancel (x-2)
{{{((x+2))/(-1(4+2x+x^2))}}} = {{{-((x+2))/((4+2x+x^2))}}}