Question 1140318



For the function ​{{{g(x)=(1/2) x-2}}}
​
find {{{g(2)+g(a)}}}

first find  {{{g(2)}}}

{{{g(2)=(1/2) 2-2}}}

{{{g(2)=(1/cross(2)) cross(2)-2}}}

{{{g(2)=1-2}}}

{{{g(3)=-1}}}


now find {{{g(a)}}}

{{{g(a)=(1/2)a-2}}}

and you have


{{{g(2)+g(a)=-1+(1/2)a-2}}}

{{{g(2)+g(a)=(1/2)a-3}}}